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(3×a+5)×5-3=292; (b-5)×2=30; (c-17)×3+15=45; [2×(d-30)-45]×3=165

Răspuns :

Răspuns:

Explicație pas cu pas:

( 3 x a + 5 ) x 5 - 3 = 292

( 3 x a + 5 ) x 5 = 292 + 3

( 3 x a + 5 ) x 5 = 295

3 x a +5 = 295 : 5

3 x a + 5 =59

3 x a = 59- 5

3 x a = 54

a = 54 : 3

a = 18

( b - 5 ) x 2 = 30

b - 5 =30 : 2

b - 5 = 15

b =15 + 5

b = 20

( c - 17) x 3 + 15 = 45

( c - 17) x 3 =45-15

( c - 17 ) x 3 =30

c - 17 = 30 : 3

c - 17 = 10

c = 10+17

c= 27

[2 x ( d - 30) - 45 ] x 3 = 165

[ 2 x ( d- 30 ) -45 ] = 165: 3

[ 2 x ( d - 30 ) - 45 ] = 55

2 x ( d - 30 ) =55 + 45

2 x ( d -30 ) = 100

( d -30 ) = 100: 2

d-30 =50

d = 50 + 30

d= 80