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Dacă: a =64+(100-9×9-5×2); b =37+(45-6×6÷6); c=23+(27÷9-24÷8) Calculează 2a+3b-4c.

Răspuns :

a=64+(100-9×9-5×2)
=64+(100-81-10)
=64+(19-10)
=64+9
=73

b=37+(45-6×6:6)
=37+(45-6)
=37+39
=76

c=23+(27:9-24:8)
=23+0
=23

2×73+3×76-4×23=146+228-92
=374-92
=282
mult succes..