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efectuati: b) [(2^10)^8+ 6^5×3^7+2^3^2]÷[(2^5)^16+6^12÷2^7 +2^8] va roggg dau coroana si tot ce vreti

Răspuns :


 b)[(2^10)^8 +6^5*3^7+2^3^2]:[(2^5)^16+6^12:2^7+2^9] =
=[(2^80 +2^5*3^12+2^9]:[(2^80+2^12*3^12:2^7+2^9] =
=[(2^80 +2^5*3^12+2^9]:[(2^80+2^5*3^12+2^9] =1

acolo era la puterea 9 nu 8