x=drum
Prima zi: x/4+6km
A doua zi: (restul reprezinta x-(prima zi))
x-x/4+6km=3x/4+6km (reprezinta restul)
(3x/4+6km)/3+4km
(3x+24)/4*1/3+4=(3x+24)/12+4km(dam factor comun 3)=(3*(x+8))/12+4km=(x+8)/4+4km
A treia zi: x-((x+8)/4)/2+4km
x-(x+8)/8+4
(8x-x+8)/8+4
De aici faci tu ca nu mai am timp...scz