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Rezolvati in Z inecuatia:
(x-1)² - (x-3)(x+3) ≥ 4 (x+7) = ?


Răspuns :

x²-2x+1-x²+9≥4x+28
-2x+10≥4x+28
-2x-4x≥28-10
-6x≥18  l·(-1)
6x≤-18
x≤-3
x²+2x+1-x²-9≥4x+28
*trec termenii*
2x+4x≥28-1+9
6x≥36
x≥36/6
x≥6
S={6,...}
Sper ca te-am ajutat. Succes!