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[tex] |z| + z -z \: conjugat = 10 - 12i[/tex]
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Răspuns :

z=a+bi   
ecuatioa  devine
la+bil+a+bi-(a-bi)=10-12i
la+bil+a+bi-a+bi=10-12i
la+bil+2bi=10-12i=>
2bi=-12i=>     2b=-12   b=-6
lzl=√(a²+b²)
√*a²+(-6)²=10
√a²+36=10
a²+36=100
a²=100-36=64
a=+/-8
z1=-8-6i
z2=8-6i