-calculez moli alcan, CnH2n+2
n= V/Vm= 560 l/22,4l/mol=25mol-
-deduc moli de Co2 ce rezulta la arderea alcanului
1mol...........................................................n,mol
CnH2n+2 +(3n+1)/2 O2-------------------> nCO2 + (n+1)H2O
25mol.......................................................25n, mol(=25n mol C)
-calculez molii de Co2 cuprinsi in volumul dat, in conditii normale
pV=nRT
10X248,62= nx0,082x(30+273)
n= 100mol CO2=100mol C
deci, 25n=100---> n=4--->butan,C4H10