Δ ABC dreptunghic ⇒ A(ABC=12×16/2=96 m²
BC=√(12²+16²)=√(144+256)=√400=20 m
P(ABC)=12+16+20=48 m
ducem AP inaltimea din A pe BC
A(ABC)=BC×AP/2
AP=2×96/20=9,6 m
A(ABM)=BM×AP/2=6×9,6/2=28,8 m²
ducem MD_I_AB (distanta de la M la AB
A(ABM)=AB×MD/2 MD=2×28,8/12=4,8 m
A(AMN)=4*9,6/2=19,2 m² (zambile)
96-19,2=76,8 m² (violete+narcise)
procent zambile = 19,2/76,8=0,25=25%
